Acids and Bases Problem?

Question

In this reaction

CH3NH2 + H20 = CH3NH3 + OH

CH3NH2 can be classified as

1. an Arrenhius acid
2. an Arrenhius base
3. a Bronsted-Lowry base
4. a Bronsted-Lowry acid
5. a Lewis acid

Answer 1

3. a Bronsted-Lowry base

This is the right answer

Answer 2

CH3NH2 is option #3. Bronsted-Lowry base. According to defintion, a Bronsted-Lowry base is the H+ or proton acceptor. In the equation, CH3NH2 becomes CH3NH3. Therefore, it accepted an H+ from H20.

Answer 3

very properly im basically gonna step you in the process the full concern ka acetic acid = a million.8x10^-5 (a million) 7bcfbacd98cfa6ce29d0ad821b14f9C27bcfbacd98cfa6ce29d0ad821b14f93O2 = C27bcfbacd98cfa6ce29d0ad821b14f93O2- H+ 7bcfbacd98cfa6ce29d0ad821b14f97bcfbacd98cfa6ce29d0ad821b14f9 I a million.0x10^-4 0 0 C -x 7bcfbacd98cfa6ce29d0ad821b14f9x 7bcfbacd98cfa6ce29d0ad821b14f9x E a million.0x10^-4-x x x a million.8x10^-5 = x^2/(a million.0x10^-4 - x) now you sparkling up for x, which represents the concentration at equillibrium od the two C27bcfbacd98cfa6ce29d0ad821b14f93O2- and 7bcfbacd98cfa6ce29d0ad821b14f97bcfbacd98cfa6ce29d0ad821b14f9. youre finding for the concentration fo 7bcfbacd98cfa6ce29d0ad821b14f97bcfbacd98cfa6ce29d0ad821b14f9, so which you go with to sparkling up for x. use the quadratic equation a million.8x10^-5 = x^2/(a million.0x10^-4 - x) x^2 = (a million.8x10^-5)(a million.0x10^-4) - a million.8x10^-5x x^2 - (a million.8x10^-5)(a million.0x10^-4) H+ a million.8x10^-5x = 0 x = .0000347M consequently [7bcfbacd98cfa6ce29d0ad821b14f97bcfbacd98cfa6ce29d0ad821b14f9] = .0000347M