Ideal Gas Law Problems?

Question

I'm so confused on this worksheet... I'm not sure how to convert L to mL

Change 1.00 L of a gas at 32oC to 27oC.
V1= V2=
T1=305. T2=30

Then another one is:
What pressure is needed to make the following
25mL of a dry gas at 65 cm to 30.0 mL

If you have any youtube videos that walk me through this, that would be nice too.

Answer 1

Temps have to be in Kelvins. K = C + 273.

Otherwise, units don't matter as long as they are the same.



V2 = V1 x T2/T1 = 1L x 300K/305K =



P2 = P1 x V1/V2 = 65cmHg? x 25mL/30mL =

Answer 2

"Change 1.00 L of a gas at 32oC to 27oC.

V1= V2=

T1=305. T2=30"



This is a Charles' Law problem:



V1= 1.00 L V2= x

T1=305. T2=300.



So:



1.00 / 305 = x / 300



solve for x



Some problems and videos:



http://www.chemteam.info/GasLaw/KMT-Gas-Laws.html



Here's a Charles Law video:



http://www.brightstorm.com/science/chemistry/kinetic-molecular-theory/charles-law/



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"Then another one is:

What pressure is needed to make the following

25mL of a dry gas at 65 cm to 30.0 mL "



65 cm is not a pressure. Let's assume you meant 65 cm of mercury. 65 cmHg is more usually expressed at 650 mmHg



This is a Boyle's Law problem:



P1V1 = P2V2



(650 mmHg) (25 mL) = (x) (30 mL)



solve for x, which will be in mmHg. Divide by 10 to get cmHg.



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"I'm not sure how to convert L to mL "



Then, all that other stuff looks pretty intimidating. Look at the videos at kahnacademy.org. You might try kentchemistry.com as well.



Good luck in your studies.



BTW,



1 L = 1000 mL, so to convert from L to ml, multiply by 1000

Answer 3

T temperature to be measured on kelvin scale.. i.e. 19+273 ok and no of moles.. weight divided by ability of molecular weight fee of R 2 b chosen accordin to the instruments used for pressur en volume.. if u use atm-l then the fee of R is 0.0821 if u use pascal-m^3 fee is 8.314 and for calculation of warmth or skill in energy, fee of R shud be approximated to 2

Answer 4

Use the equation V/T= V'/T'

You do not need to convert to mL (1000mL = 1 L)

You do need to have both temperatures in absolute.



1.00L/305K = ? L/300K